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However, this isn t really very useful, since it doesn t take into account that adding seven to the current day of the month could put us into the next month, or possibly even into the next year Instead, you should add seven days to the value that you supply to the localtime function For example:

($mday,$mon,$year) = (localtime($time+(7*24*60*60)))[35]; $mon++; $year+=1900; print "Date will be $mday/$mon/$year\n";

Here, we ve added seven days (7 times 24 hours, times 60 minutes, times 60 seconds); because we re asking localtime to do the calculation on the raw value we ll get the correct date You can do similar calculations for other values too, for example:

11:

Which of the following code fragments, inserted independently at line 10, will probably run most (or all) of the main thread s run() method invocation before running most of the t1 thread s run() method invocation (Choose all that apply) A t1setPriority(1); new Mosey()run(); t1start(); B t1setPriority(9); new Mosey()run(); t1start();

$time -= 24*60*60; $time += 45*60;

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The limitation of this system is that it only really works on days, hours, minutes, and seconds The moment you want to add months or years, the process gets more complicated, as you would need to determine how many days in the month or year in order to get the correct epoch value To resolve both problems, you might consider using a function like the one below, which will add or subtract any time value to any other time value It s based on the Visual Basic DateAdd function:

use Time::Local; sub DateAdd { my ($interval, $number, $time, $sec, $min, $hour, $mday, $mon, $year); if (@_ <= 3) { if (@_ == 2) { $time = time(); ($interval, $number) = @_; } else { ($interval, $number, $time) = @_; } ($sec,$min,$hour,$mday,$mon,$year) = (localtime($time))[05]; } else { ($interval, $number, $time, $sec, $min, $hour, $mday, $mon, $year) = @_; } $year += $number if ($interval eq 'yyyy'); if (($interval eq 'q') || ($interval eq 'm')) {

C t1setPriority(1); t1start(); new Mosey()run(); D t1setPriority(8); t1start(); new Mosey()run(); Answer (for Objective 42): A, B, and C are correct For A and B, the main thread executes the run() method before it starts t1 C is correct because t1 is set to a low priority, giving the main thread scheduling priority D is incorrect because by setting t1 s priority to 8, the t1 thread will tend to execute mostly before the main thread

$mon += $number if ($interval eq 'm'); $mon += ($number*3) if ($interval eq 'q'); if ($mon > 11) { $year += int ($mon/12); $mon = $mon % 12; } } $newtime = timelocal($sec,$min,$hour,$mday,$mon,$year); $newtime += ($number*24*60*60) if (($interval eq 'y') || ($interval eq 'd') || ($interval eq 'w')); $newtime += ($number*7*24*60*60) if ($interval eq 'ww'); $newtime += ($number*60*60) if ($interval eq 'h'); $newtime += ($number*60) if ($interval eq 'n'); $newtime += $number if ($interval eq 's'); return $newtime; }

To use this function, supply the interval type (as shown in Table 11-5) and the number to be added If you don t supply a time value, then the current time will be used Alternatively, you can supply either an epoch value or the seconds, minutes, hours, day of the month, month, and year, in the same format as that returned by localtime For example, the following adds three weeks to the current date (1st April), and then outputs a date/time string of the new value:

print scalar localtime(DateAdd('ww',3)),"\n";

13 Given:

Sat Apr 22 13:50:51 2000

11:

yyyy q m y d w ww h n s Table 11-5

37 38 39 40 41 42 boolean b = false; int i = 7; double d = 123; float f = 456f; // insert code here

returns a four-element list giving the CPU time used by the current process for user-derived and system-derived tasks, and the time used by any children for userand system-derived tasks:

($user, $system, $child, $childsystem) = times;

The information is obtained from the system times() function, which reports the time in seconds to a granularity of a hundredth of a second This affords better timing

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